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A line has a slope of $0$ and a $y$ -intercept of $-\frac{8}{3}$ . Write its equation in slope-intercept form. $\newline$ Write your answer using integers, proper fractions, and improper fractions in simplest form.

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Slope-intercept form: write an equation

Full solution

Q. A line has a slope of

0

and a

y

-intercept of

-\frac{8}{3}

. Write its equation in slope-intercept form.

\newline

Write your answer using integers, proper fractions, and improper fractions in simplest form.

Identify Linear Equation Form: Identify the slope-intercept form of a linear equation. $\newline$ The slope-intercept form of a linear equation is $y = mx + b$ , where $m$ is the slope and $b$ is the y-intercept.
Insert Given Values: Insert the given slope and y-intercept into the slope-intercept form. $\newline$ We are given the slope $m$ as $0$ and the y-intercept $b$ as $-\frac{8}{3}$ . Substituting these values into the slope-intercept form, we get $y = (0)x + \left(-\frac{8}{3}\right)$ .
Simplify Equation: Simplify the equation. $\newline$ Since the slope is $0$ , the term $(0)x$ is equal to $0$ , and therefore it can be removed from the equation. This leaves us with $y = -\frac{8}{3}$ .
Check for Errors: Check for any mathematical errors. $\newline$ There are no multiplication or addition errors, and the simplification is correct. The equation $y = -\frac{8}{3}$ correctly represents a horizontal line with a $y$ -intercept of $-\frac{8}{3}$ .

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\newline

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\newline

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Question

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\newline

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\newline

\newline

\text{(A)horizontal line}

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Question

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\newline

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\newline

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Question

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