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A lake near the Arctic Circle is covered by a 22-meter- thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After 33 weeks, the sheet is only 1.251.25 meters thick. Let yy represent the ice sheet's thickness (in meters) after 22 weeks. Complete the equation for the relationship between the thickness and number of weeks. y=y=

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Q. A lake near the Arctic Circle is covered by a 22-meter- thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After 33 weeks, the sheet is only 1.251.25 meters thick. Let yy represent the ice sheet's thickness (in meters) after 22 weeks. Complete the equation for the relationship between the thickness and number of weeks. y=y=
  1. Calculate melting rate: Determine the rate of ice melting per week.\newlineThe ice thickness decreases from 22 meters to 1.251.25 meters over 33 weeks.\newlineChange in thickness = 21.25=0.752 - 1.25 = 0.75 meters.\newlineTime = 33 weeks.\newlineRate of melting = Change in thickness / Time = 0.750.75 meters / 33 weeks = 0.250.25 meters per week.
  2. Write thickness equation: Write the equation for the thickness of the ice sheet after xx weeks.\newlineInitial thickness = 22 meters.\newlineDecrease per week = 0.250.25 meters.\newlineThickness after xx weeks = Initial thickness - (Decrease per week * xx).\newliney=20.25xy = 2 - 0.25x.
  3. Find thickness after 22 weeks: Substitute x=2x = 2 into the equation to find the thickness after 22 weeks.y=20.25×2=20.5=1.5y = 2 - 0.25 \times 2 = 2 - 0.5 = 1.5 meters.

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