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A jug of wate has a mass of 19 kg 67 g19\,\text{kg}\,67\,\text{g}. The mass of the water is 1871 g1871\,\text{g}. What is the mass of the empty jug?

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Q. A jug of wate has a mass of 19 kg 67 g19\,\text{kg}\,67\,\text{g}. The mass of the water is 1871 g1871\,\text{g}. What is the mass of the empty jug?
  1. Calculate total mass: Now, calculate the total mass of the jug in grams.\newline19×1000=1900019 \times 1000 = 19000 g\newline1900019000 g + 6767 g = 1906719067 g
  2. Subtract water mass: Next, subtract the mass of the water from the total mass of the jug to find the mass of the empty jug. 19067 g−1871 g=17196 g19067 \, \text{g} - 1871 \, \text{g} = 17196 \, \text{g}

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