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A function, 
f, has domain 
-10 <= x <= 20 and range 
-40 <= f(x) <= -10. Select each statement that must be false about 
f(x).


{:[f(1)=-13],[f(-10)=-40]:}

◻f(1)=13

f(-9)=88

f(5)=-40

f(0)=0

f(-15)=-20

77. A function, f f , has domain 10x20 -10 \leq x \leq 20 and range 40f(x)10 -40 \leq f(x) \leq-10 . Select each statement that must be false about f(x) f(x) .\newlinef(1)=13f(10)=40 \begin{array}{c} f(1)=-13 \\ f(-10)=-40 \end{array} \newlinef(1)=13 \square f(1)=13 \newlinef(9)=88 f(-9)=88 \newlinef(5)=40 f(5)=-40 \newlinef(0)=0 f(0)=0 \newlinef(15)=20 f(-15)=-20

Full solution

Q. 77. A function, f f , has domain 10x20 -10 \leq x \leq 20 and range 40f(x)10 -40 \leq f(x) \leq-10 . Select each statement that must be false about f(x) f(x) .\newlinef(1)=13f(10)=40 \begin{array}{c} f(1)=-13 \\ f(-10)=-40 \end{array} \newlinef(1)=13 \square f(1)=13 \newlinef(9)=88 f(-9)=88 \newlinef(5)=40 f(5)=-40 \newlinef(0)=0 f(0)=0 \newlinef(15)=20 f(-15)=-20
  1. Check Range for f(1)f(1): Check if f(1)=13f(1) = 13 is possible given the range.\newlineRange is 40f(x)10-40 \leq f(x) \leq -10, so f(1)=13f(1) = 13 is outside the range.
  2. Check Range for f(9)f(-9): Check if f(9)=88f(-9) = 88 is possible given the range.\newlineRange is 40f(x)10-40 \leq f(x) \leq -10, so f(9)=88f(-9) = 88 is outside the range.
  3. Check Range for f(5)f(5): Check if f(5)=40f(5) = -40 is possible given the range.\newlineRange is 40f(x)10-40 \leq f(x) \leq -10, so f(5)=40f(5) = -40 is within the range.
  4. Check Range for f(0)f(0): Check if f(0)=0f(0) = 0 is possible given the range.\newlineRange is 40f(x)10-40 \leq f(x) \leq -10, so f(0)=0f(0) = 0 is outside the range.
  5. Check Domain for f(15)f(-15): Check if f(15)=20f(-15) = -20 is possible given the domain.\newlineDomain is 10x20-10 \leq x \leq 20, so f(15)=20f(-15) = -20 is outside the domain.

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