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A forest has 800 pine trees, but a disease is introduced that kills 
(1)/(4) of the pine trees in the forest every year.
Write a function that gives the number of pine trees remaining 
P(t) in the forest 
t years after the disease is introduced.

P(t)=◻+=^(+)

A forest has 800800 pine trees, but a disease is introduced that kills 14 \frac{1}{4} of the pine trees in the forest every year.\newlineWrite a function that gives the number of pine trees remaining P(t) P(t) in the forest t t years after the disease is introduced.\newlineP(t)= P(t)=\square

Full solution

Q. A forest has 800800 pine trees, but a disease is introduced that kills 14 \frac{1}{4} of the pine trees in the forest every year.\newlineWrite a function that gives the number of pine trees remaining P(t) P(t) in the forest t t years after the disease is introduced.\newlineP(t)= P(t)=\square
  1. Understand Decay Pattern: Step 11: To write the function, we need to understand the pattern of decay of the pine trees. Since one quarter of the trees are killed each year, this means that each year, the forest retains three quarters (or 75%75\%) of its pine trees from the previous year. This is a geometric decay with a decay factor of 0.750.75 (since 114=341 - \frac{1}{4} = \frac{3}{4}).
  2. Exponential Decay Function: Step 22: The general form of an exponential decay function is P(t)=P0×(decay_factor)tP(t) = P_0 \times (\text{decay\_factor})^t, where P0P_0 is the initial quantity and decay\_factor is the factor by which the quantity decreases each year. In this case, P0P_0 is the initial number of pine trees, which is 800800, and the decay factor is 0.750.75.
  3. Substitute Values: Step 33: Substitute the values into the exponential decay function to get the specific function for this problem. P(t)=800×(0.75)tP(t) = 800 \times (0.75)^t. This function will give us the number of pine trees remaining in the forest tt years after the disease is introduced.

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