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A florist orders exactly 
(1)/(3) gallons of nutrient-rich water for each bushel of flowers he buys. The florist buys bushels of flowers at 
$1.20 per bushel and gallons of nutrient-rich water at 
$0.60 per gallon. Which of the following equations gives the total cost, 
C(b), in dollars, for 
b bushels of flowers and the nutrient-rich water ordered for them?
Choose 1 answer:
(A) 
C(b)=(1.2+0.2)*b
(B) 
C(b)=3*0.6*b
(c) 
C(b)=(1.2+0.6)*b
(D) 
C(b)=7*0.6*b

A florist orders exactly 13 \frac{1}{3} gallons of nutrient-rich water for each bushel of flowers he buys. The florist buys bushels of flowers at $1.20 \$ 1.20 per bushel and gallons of nutrient-rich water at $0.60 \$ 0.60 per gallon. Which of the following equations gives the total cost, C(b) C(b) , in dollars, for b b bushels of flowers and the nutrient-rich water ordered for them?\newlineChoose 11 answer:\newline(A) C(b)=(1.2+0.2)b C(b)=(1.2+0.2) \cdot b \newline(B) C(b)=30.6b C(b)=3 \cdot 0.6 \cdot b \newline(c) C(b)=(1.2+0.6)b C(b)=(1.2+0.6) \cdot b \newline(D) C(b)=70.6b C(b)=7 \cdot 0.6 \cdot b

Full solution

Q. A florist orders exactly 13 \frac{1}{3} gallons of nutrient-rich water for each bushel of flowers he buys. The florist buys bushels of flowers at $1.20 \$ 1.20 per bushel and gallons of nutrient-rich water at $0.60 \$ 0.60 per gallon. Which of the following equations gives the total cost, C(b) C(b) , in dollars, for b b bushels of flowers and the nutrient-rich water ordered for them?\newlineChoose 11 answer:\newline(A) C(b)=(1.2+0.2)b C(b)=(1.2+0.2) \cdot b \newline(B) C(b)=30.6b C(b)=3 \cdot 0.6 \cdot b \newline(c) C(b)=(1.2+0.6)b C(b)=(1.2+0.6) \cdot b \newline(D) C(b)=70.6b C(b)=7 \cdot 0.6 \cdot b
  1. Calculate Cost of Flowers: Calculate the cost of bb bushels of flowers.\newlineCost of flowers = $1.20\$1.20 per bushel * bb bushels
  2. Calculate Cost of Water: Calculate the cost of nutrient-rich water needed for bb bushels of flowers.\newlineSince 11 bushel requires 13\frac{1}{3} gallons, bb bushels require 13×b\frac{1}{3} \times b gallons.\newlineCost of water = $(0.60)\$(0.60) per gallon ×13×b\times \frac{1}{3} \times b gallons
  3. Simplify Water Cost: Simplify the cost of water.\newlineCost of water = $0.60×13×b\$0.60 \times \frac{1}{3} \times b\newlineCost of water = $0.20×b\$0.20 \times b
  4. Find Total Cost: Add the cost of flowers and the cost of water to get the total cost C(b)C(b).C(b)=($(1.20)×b)+($(0.20)×b)C(b) = (\$(1.20) \times b) + (\$(0.20) \times b)C(b)=$1.20b+$0.20bC(b) = \$1.20b + \$0.20b
  5. Combine Like Terms: Combine like terms to find the equation for C(b)C(b).C(b)=($(1.20)+$(0.20))×bC(b) = (\$(1.20) + \$(0.20)) \times bC(b)=$(1.40)×bC(b) = \$(1.40) \times b

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