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A direct variation includes the points (3,15)(3,15) and (1,n)(1,n). Find nn. Write and solve a direct variation equation to find the answer.\newlinen=___n = \_\_\_

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Q. A direct variation includes the points (3,15)(3,15) and (1,n)(1,n). Find nn. Write and solve a direct variation equation to find the answer.\newlinen=___n = \_\_\_
  1. Select equation direct variation: Select the equation that represents direct variation.\newlineSince yy varies directly with xx, we use the direct variation equation: y=kxy = kx.
  2. Find constant proportionality: Use the given point (3,15)(3,15) to find the constant of proportionality (k)(k). Substitute the values in y=kxy = kx. Plug in 33 for xx and 1515 for yy in y=kxy = kx. 15=k×315 = k \times 3
  3. Solve constant proportionality: Solve for the constant of proportionality kk.\newlineDivide both sides by 33 to isolate kk.\newline153=(k×3)3\frac{15}{3} = \frac{(k \times 3)}{3}\newline5=k5 = k\newlinek=5k = 5
  4. Write direct variation equation: Write the direct variation equation using the value of kk.\newlineSince k=5k = 5, the direct variation equation is y=5xy = 5x.
  5. Find nn: Use the direct variation equation to find nn when x=1x = 1. Substitute 11 for xx in y=5xy = 5x to find nn. n=5×1n = 5 \times 1 n=5n = 5

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