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A culture of bacteria has an initial population of 77000 bacteria and doubles every 2 hours. Using the formula 
P_(t)=P_(0)*2^((t)/(d)), where 
P_(t) is the population after 
t hours, 
P_(0) is the initial population, 
t is the time in hours and 
d is the doubling time, what is the population of bacteria in the culture after 15 hours, to the nearest whole number?
Answer:

A culture of bacteria has an initial population of 7700077000 bacteria and doubles every 22 hours. Using the formula Pt=P02td P_{t}=P_{0} \cdot 2^{\frac{t}{d}} , where Pt P_{t} is the population after t t hours, P0 P_{0} is the initial population, t t is the time in hours and d d is the doubling time, what is the population of bacteria in the culture after 1515 hours, to the nearest whole number?\newlineAnswer:

Full solution

Q. A culture of bacteria has an initial population of 7700077000 bacteria and doubles every 22 hours. Using the formula Pt=P02td P_{t}=P_{0} \cdot 2^{\frac{t}{d}} , where Pt P_{t} is the population after t t hours, P0 P_{0} is the initial population, t t is the time in hours and d d is the doubling time, what is the population of bacteria in the culture after 1515 hours, to the nearest whole number?\newlineAnswer:
  1. Identify initial population and doubling time: Identify the initial population P0P_0 and the doubling time dd. The initial population of bacteria, P0P_0, is given as 7700077000 bacteria. The doubling time, dd, is given as every 22 hours.
  2. Write population formula: Write down the formula for the population after tt hours.\newlineThe formula given is P(t)=P(0)×2(t/d)P_{(t)} = P_{(0)} \times 2^{(t/d)}, where P(t)P_{(t)} is the population after tt hours, P(0)P_{(0)} is the initial population, tt is the time in hours, and dd is the doubling time in hours.
  3. Substitute given values: Substitute the given values into the formula.\newlineWe need to find the population after 1515 hours, so t=15t = 15. The initial population P0P_{0} is 7700077000, and the doubling time dd is 22 hours. Substituting these values into the formula gives us:\newlineP15=77000×2152P_{15} = 77000 \times 2^{\frac{15}{2}}
  4. Calculate the exponent: Calculate the exponent.\newlineTo calculate 2(15/2)2^{(15/2)}, we first divide 1515 by 22, which gives us 7.57.5. Then we raise 22 to the power of 7.57.5.\newline2(15/2)=27.52^{(15/2)} = 2^{7.5}
  5. Calculate 27.52^{7.5}: Calculate 27.52^{7.5}. Using a calculator, we find that 27.52^{7.5} is approximately 181.01933598375618181.01933598375618.
  6. Multiply by growth factor: Multiply the initial population by the growth factor.\newlineNow we multiply the initial population of 7700077000 by the growth factor we just calculated.\newlineP15=77000×181.01933598375618P_{15} = 77000 \times 181.01933598375618
  7. Calculate final population: Calculate the final population. Multiplying 7700077000 by 181.01933598375618181.01933598375618 gives us approximately 13938489.2697561813938489.26975618.
  8. Round to nearest whole number: Round the population to the nearest whole number.\newlineThe population of bacteria after 1515 hours, rounded to the nearest whole number, is approximately 1393848913938489.

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