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A company finds that if they price their product at 
$55, they can sell 690 items of it. For every dollar increase in the price, the number of items sold will decrease by 10 .
What is the maximum revenue possible in this situation? (Do not use commas when entering the answer) 
$ 
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What price will guarantee the maximum revenue? $ 
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A company finds that if they price their product at $55 \$ 55 , they can sell 690690 items of it. For every dollar increase in the price, the number of items sold will decrease by 1010 .\newlineWhat is the maximum revenue possible in this situation? (Do not use commas when entering the answer) $ \$ ________\newlineWhat price will guarantee the maximum revenue?$\$ ____________

Full solution

Q. A company finds that if they price their product at $55 \$ 55 , they can sell 690690 items of it. For every dollar increase in the price, the number of items sold will decrease by 1010 .\newlineWhat is the maximum revenue possible in this situation? (Do not use commas when entering the answer) $ \$ ________\newlineWhat price will guarantee the maximum revenue?$\$ ____________
  1. Define revenue function: Define the revenue function based on the given information. Let pp be the price of the product. The initial price is $55\$55, and the initial quantity sold is 690690 items. For every $1\$1 increase in price, the quantity sold decreases by 1010 items. The revenue RR can be expressed as R=p×qR = p \times q, where qq is the quantity sold at price pp.
  2. Express quantity as function: Express quantity qq as a function of price pp. Since the quantity decreases by 1010 items for each $1\$1 increase in price from $55\$55, we have q=69010(p55)q = 690 - 10(p - 55). Simplifying, q=69010p+550q = 690 - 10p + 550, which further simplifies to q=124010pq = 1240 - 10p.
  3. Substitute quantity in revenue: Substitute qq in the revenue function. So, R=p×(124010p)=1240p10p2R = p \times (1240 - 10p) = 1240p - 10p^2. This is a quadratic equation in terms of pp, where the coefficient of p2p^2 is negative, indicating a downward opening parabola.
  4. Find vertex for maximum revenue: Find the vertex of the parabola to determine the maximum revenue. The vertex formula for a parabola ax2+bx+cax^2 + bx + c is given by x=b/(2a)x = -b/(2a). Here, a=10a = -10 and b=1240b = 1240, so p=1240/(2×10)=62p = -1240 / (2 \times -10) = 62.
  5. Calculate maximum revenue: Calculate the maximum revenue by substituting p=62p = 62 into the revenue equation. R=62×(124010×62)=62×620=38440R = 62 \times (1240 - 10 \times 62) = 62 \times 620 = 38440.

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