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A club is going to send 4 of its 10 members to represent the club at a conference.
How many different groups of 4 members can they send?

A club is going to send 44 of its 1010 members to represent the club at a conference.\newlineHow many different groups of 44 members can they send?

Full solution

Q. A club is going to send 44 of its 1010 members to represent the club at a conference.\newlineHow many different groups of 44 members can they send?
  1. Calculate factorial of 1010: To solve this problem, we need to calculate the number of combinations of 1010 members taken 44 at a time. This is a combinatorial problem where order does not matter, and we can use the combination formula which is C(n,k)=n!k!(nk)!C(n, k) = \frac{n!}{k!(n-k)!}, where nn is the total number of items, kk is the number of items to choose, and “!!” denotes factorial.
  2. Calculate factorial of 44: First, we calculate the factorial of 1010, which is 10!=10×9×8×7×6×5×4×3×2×110! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1.
  3. Calculate factorial of difference: Next, we calculate the factorial of 44, which is 4!=4×3×2×14! = 4 \times 3 \times 2 \times 1.
  4. Apply combination formula: Then, we calculate the factorial of the difference between 1010 and 44, which is 6!=6×5×4×3×2×16! = 6 \times 5 \times 4 \times 3 \times 2 \times 1.
  5. Substitute factorial values: Now we can plug these values into the combination formula: C(10,4)=10!4!×(104)!C(10, 4) = \frac{10!}{4! \times (10-4)!}.
  6. Simplify the equation: Substitute the factorial values into the formula: C(10,4)=10×9×8×7×6×5×4×3×2×1(4×3×2×1)×(6×5×4×3×2×1)C(10, 4) = \frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{(4 \times 3 \times 2 \times 1) \times (6 \times 5 \times 4 \times 3 \times 2 \times 1)}.
  7. Perform division and multiplication: We can simplify the equation by canceling out the common factors in the numerator and the denominator. The 6×5×4×3×2×16 \times 5 \times 4 \times 3 \times 2 \times 1 in the denominator cancels with the same factors in the numerator, leaving us with: C(10,4)=10×9×8×74×3×2×1C(10, 4) = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1}.
  8. Final result: Perform the division and multiplication: C(10,4)=10×9×8×724=90×7=630C(10, 4) = \frac{10 \times 9 \times 8 \times 7}{24} = 90 \times 7 = 630.
  9. Final result: Perform the division and multiplication: C(10,4)=10×9×8×724=90×7=630C(10, 4) = \frac{10 \times 9 \times 8 \times 7}{24} = 90 \times 7 = 630.Therefore, the club can send 630630 different groups of 44 members to represent it at the conference.

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