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A box contains 44 red cards, 66 blue cards, and 1010 green cards. What is the smallest number of cards we must remove from the box to make sure that we have 22 cards of the same color?\newlineE. 22\newlineF. 33\newlineG. 44\newlineH. 1717

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Q. A box contains 44 red cards, 66 blue cards, and 1010 green cards. What is the smallest number of cards we must remove from the box to make sure that we have 22 cards of the same color?\newlineE. 22\newlineF. 33\newlineG. 44\newlineH. 1717
  1. Consider Worst-Case Scenario: We start by considering the worst-case scenario where we pick the maximum number of cards without getting two of the same color. We can pick all the red cards, which are 44, and then we can pick all the blue cards, which are 66. So far, we have picked 4+6=104 + 6 = 10 cards without getting two of the same color.
  2. Pick Additional Green Card: Now, if we pick one more card, it has to be green since we've already picked all the red and blue cards. This guarantees that we will have two green cards because there are 1010 green cards in total.
  3. Remove Cards for Same Color: So, the smallest number of cards we must remove to ensure we have two cards of the same color is the total number of red and blue cards we picked plus one more card, which is 10+1=1110 + 1 = 11 cards.

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