A bottle of white wine at room temperature 68∘F is placed in a refrigerator at 4 p.m. Its temperature after t hr is changing at the rate of −18e−0.6t∘F/hour. By how many degrees will the temperature of the wine have dropped by 7 p.m.? What will the temperature of the wine be at 7 p.m.?
Q. A bottle of white wine at room temperature 68∘F is placed in a refrigerator at 4 p.m. Its temperature after t hr is changing at the rate of −18e−0.6t∘F/hour. By how many degrees will the temperature of the wine have dropped by 7 p.m.? What will the temperature of the wine be at 7 p.m.?
Calculate Time Difference: The wine is placed in the fridge at 4 p.m. and we want to know the temperature at 7 p.m., so we calculate the time difference.Time difference = 7 p.m. - 4 p.m. = 3 hours.
Find Temperature Change Rate: The temperature change rate is given by the function −18e−0.6t. We need to plug t=3 into the function to find the temperature drop after 3 hours. Temperature drop = −18e(−0.6∗3).
Calculate Exponent Part: Now we calculate the exponent part: −0.6×3=−1.8.
Calculate e−1.8: Next, we calculate e−1.8. Using a calculator, e−1.8≈0.1653.
Find Temperature Drop: Now we multiply this by −18 to find the temperature drop.Temperature drop = −18×0.1653≈−2.9754.Oops, we made a mistake here. The temperature drop should be a positive value since we're talking about how much it has decreased, not the direction of change.
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