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A block with a mass of 
30kg is located on a horizontal, frictionless tabletop. This block is connected by a rope to another block with a mass of 
10kg. The rope is looped through a pulley on the table's edge so that the less massive block is hanging over the edge. What is the magnitude of the acceleration of the larger block across the table?

33. A block with a mass of 30 kg 30 \mathrm{~kg} is located on a horizontal, frictionless tabletop. This block is connected by a rope to another block with a mass of 10 kg 10 \mathrm{~kg} . The rope is looped through a pulley on the table's edge so that the less massive block is hanging over the edge. What is the magnitude of the acceleration of the larger block across the table?

Full solution

Q. 33. A block with a mass of 30 kg 30 \mathrm{~kg} is located on a horizontal, frictionless tabletop. This block is connected by a rope to another block with a mass of 10 kg 10 \mathrm{~kg} . The rope is looped through a pulley on the table's edge so that the less massive block is hanging over the edge. What is the magnitude of the acceleration of the larger block across the table?
  1. Identify Horizontal Force: Now, since the tabletop is frictionless, the only horizontal force acting on the 3030kg block is the tension in the rope, which is equal to the force of gravity on the 1010kg block (9898 N). We can use this force to find the acceleration of the 3030kg block.\newlineApply Newton's second law to the 3030kg block:\newlineF=maF = ma\newline9898 N = 3030kg ×\times aa\newline101000\newline101011 m/s101022
  2. Apply Newton's Second Law: Round the acceleration to two decimal places for the final answer:\newlinea=3.27m/s2a = 3.27 \, \text{m/s}^2

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