3. A block with a mass of 30kg is located on a horizontal, frictionless tabletop. This block is connected by a rope to another block with a mass of 10kg. The rope is looped through a pulley on the table's edge so that the less massive block is hanging over the edge. What is the magnitude of the acceleration of the larger block across the table?
Q. 3. A block with a mass of 30kg is located on a horizontal, frictionless tabletop. This block is connected by a rope to another block with a mass of 10kg. The rope is looped through a pulley on the table's edge so that the less massive block is hanging over the edge. What is the magnitude of the acceleration of the larger block across the table?
Identify Horizontal Force: Now, since the tabletop is frictionless, the only horizontal force acting on the 30kg block is the tension in the rope, which is equal to the force of gravity on the 10kg block (98 N). We can use this force to find the acceleration of the 30kg block.Apply Newton's second law to the 30kg block:F=ma98 N = 30kg ×a100101 m/s102
Apply Newton's Second Law: Round the acceleration to two decimal places for the final answer:a=3.27m/s2
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