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A big ship drops its anchor.

E represents the anchor's elevation relative to the water's surface (in meters) as a function of time
t (in seconds).

E=-2.4 t+75
How far does the anchor drop every 5 seconds?

◻ meters

A big ship drops its anchor. $\newline$ $E$ represents the anchor's elevation relative to the water's surface (in meters) as a function of time $t$ (in seconds). $\newline$ $E=-2.4 t+75$ $\newline$ How far does the anchor drop every $5$ seconds? $\newline$ $\square$ meters

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Relate position, velocity, speed, and acceleration using derivatives

Full solution

Q. A big ship drops its anchor.

\newline

E

represents the anchor's elevation relative to the water's surface (in meters) as a function of time

t

(in seconds).

\newline

E=-2.4 t+75

\newline

How far does the anchor drop every

5

seconds?

\newline

\square

meters

Calculate elevation change: First, we need to calculate the elevation change after $5$ seconds. We plug $t=5$ into the equation $E=-2.4t+75$ .
Substitute $t=5$ : So, $E=-2.4(5)+75$ .
Perform multiplication: That gives us $E=-12+75$ .
Final elevation calculation: Now, we do the math: $E=63$ meters.

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