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A basketball team stopped at a fast-food restaurant after a game. They are divided into two groups. One group bough 5 chicken sandwiches and 7 hamburgers for a cost of 
$24.90. The second group spent 
$28.80 and bought 5 chicken sandwiches and 9 hamburgers. Write a system of equations to represent the situation. Then use it to find the cost of each chicken sandwich and each hamburger?

A basketball team stopped at a fast-food restaurant after a game. They are divided into two groups. One group bough 55 chicken sandwiches and 77 hamburgers for a cost of $24.90 \$ 24.90 . The second group spent $28.80 \$ 28.80 and bought 55 chicken sandwiches and 99 hamburgers. Write a system of equations to represent the situation. Then use it to find the cost of each chicken sandwich and each hamburger?

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Q. A basketball team stopped at a fast-food restaurant after a game. They are divided into two groups. One group bough 55 chicken sandwiches and 77 hamburgers for a cost of $24.90 \$ 24.90 . The second group spent $28.80 \$ 28.80 and bought 55 chicken sandwiches and 99 hamburgers. Write a system of equations to represent the situation. Then use it to find the cost of each chicken sandwich and each hamburger?
  1. Write Equations: Write the system of equations based on the orders of the two groups.\newlineGroup 11: 55 chicken sandwiches and 77 hamburgers for $24.90\$24.90.\newlineGroup 22: 55 chicken sandwiches and 99 hamburgers for $28.80\$28.80.\newlineLet xx be the cost of a chicken sandwich and yy be the cost of a hamburger.\newlineThe equations are:\newline5x+7y=24.905x + 7y = 24.90 (Equation 11)\newline5x+9y=28.805x + 9y = 28.80 (Equation 22)
  2. Use Elimination: Use elimination to solve the system of equations.\newlineWe can eliminate xx by subtracting Equation 11 from Equation 22.\newline(5x+9y)(5x+7y)=28.8024.90(5x + 9y) - (5x + 7y) = 28.80 - 24.90\newline5x+9y5x7y=28.8024.905x + 9y - 5x - 7y = 28.80 - 24.90\newline2y=3.902y = 3.90
  3. Solve for y: Solve for y, the cost of a hamburger.\newline2y=3.902y = 3.90\newliney=3.902y = \frac{3.90}{2}\newliney=1.95y = 1.95\newlineSo, each hamburger costs $1.95\$1.95.
  4. Substitute and Solve: Substitute the value of yy into one of the original equations to solve for xx, the cost of a chicken sandwich.\newlineUsing Equation 11:\newline5x+7(1.95)=24.905x + 7(1.95) = 24.90\newline5x+13.65=24.905x + 13.65 = 24.90\newline5x=24.9013.655x = 24.90 - 13.65\newline5x=11.255x = 11.25\newlinex=11.255x = \frac{11.25}{5}\newlinex=2.25x = 2.25\newlineSo, each chicken sandwich costs $2.25\$2.25.

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