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$A+B=126$ , and $B+C=50$ then what is the value of $A+B+C=?$

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Write and solve direct variation equations

Full solution

Q.

A+B=126

, and

B+C=50

then what is the value of

A+B+C=?

Write Equations: We know $A+B=126$ . Let's write that down. $A+B = 126$
Add Equations: Also, $B+C=50$ . $\newline$ Write that too. $\newline$ $B+C = 50$
Combine Terms: To find $A+B+C$ , we can add the two equations together. $\newline$ So, $(A+B) + (B+C) = 126 + 50$
Simplify Equation: Now, let's add them up. $A + B + B + C = 176$
Subtract B: But wait, we got B twice in the equation. $\newline$ We need to combine B's. $\newline$ $A + 2B + C = 176$
Subtract B: But wait, we got B twice in the equation. $\newline$ We need to combine B's. $\newline$ $A + 2B + C = 176$ We don't need $2B$ , just $B$ . $\newline$ So, we gotta subtract $B$ from both sides. $\newline$ $A + B + C = 176 - B$

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