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a and 
b are the intercepts made by 
a line on the co-ordinate axes. If 
3a=b and the line passes through 
(1,3), then the equation of the line is

aa and bb are the intercepts made by a line on the co-ordinate axes. If 3a=b3a=b and the line passes through (1,3) (1,3) , then the equation of the line is \newline A) x+3y=10x+3y =10 \newline B) 3x+y=63x+y =6 \newline C) x3y+8=0x-3y+8 =0 \newline D) 3x2+3=03x-2+3 =0

Full solution

Q. aa and bb are the intercepts made by a line on the co-ordinate axes. If 3a=b3a=b and the line passes through (1,3) (1,3) , then the equation of the line is \newline A) x+3y=10x+3y =10 \newline B) 3x+y=63x+y =6 \newline C) x3y+8=0x-3y+8 =0 \newline D) 3x2+3=03x-2+3 =0
  1. Identify Relationship: Identify the relationship between the intercepts aa and bb. Given that 3a=b3a = b, we can express bb in terms of aa. Calculation: b=3ab = 3a
  2. Determine Equation: Determine the equation of the line using intercept form.\newlineThe intercept form of a line's equation is xa+yb=1\frac{x}{a} + \frac{y}{b} = 1.\newlineSince we know b=3ab = 3a, we can substitute bb in the equation.\newlineCalculation: xa+y(3a)=1\frac{x}{a} + \frac{y}{(3a)} = 1
  3. Use Given Point: Use the given point (1,3)(1,3) to find the value of aa.\newlineSubstitute x=1x = 1 and y=3y = 3 into the equation xa+y3a=1\frac{x}{a} + \frac{y}{3a} = 1.\newlineCalculation: 1a+33a=1\frac{1}{a} + \frac{3}{3a} = 1
  4. Simplify Equation: Simplify the equation to solve for aa. Combine the terms on the left side of the equation. Calculation: 1a+1a=1\frac{1}{a} + \frac{1}{a} = 1 Calculation: 2a=1\frac{2}{a} = 1
  5. Solve for a: Solve for a. Multiply both sides by aa to isolate aa. Calculation: 2=a2 = a
  6. Find Value of b: Find the value of b using the relationship b=3ab = 3a.\newlineSubstitute a=2a = 2 into b=3ab = 3a.\newlineCalculation: b=3×2b = 3 \times 2\newlineCalculation: b=6b = 6
  7. Write Final Equation: Write the final equation of the line using the values of aa and bb. Substitute a=2a = 2 and b=6b = 6 into the intercept form equation xa+yb=1\frac{x}{a} + \frac{y}{b} = 1. Calculation: x2+y6=1\frac{x}{2} + \frac{y}{6} = 1
  8. Multiply for Standard Form: Multiply through by the least common multiple of the denominators to get the standard form of the equation.\newlineCalculation: 3(x2)+(y6)=33(\frac{x}{2}) + (\frac{y}{6}) = 3\newlineCalculation: 3x2+y6=3\frac{3x}{2} + \frac{y}{6} = 3\newlineCalculation: 6(3x2+y6)=6(3)6(\frac{3x}{2} + \frac{y}{6}) = 6(3)\newlineCalculation: 9x+y=189x + y = 18

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