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a^(2)-b^(2)=(a+b)(a-b)

a2b2=(a+b)(ab) a^{2}-b^{2}=(a+b)(a-b)

Full solution

Q. a2b2=(a+b)(ab) a^{2}-b^{2}=(a+b)(a-b)
  1. Expand using distributive property: To prove the identity a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b), we will expand the right-hand side of the equation using the distributive property (also known as the FOIL method for binomials).
  2. Multiply first terms: First, we multiply the first terms of each binomial: a×a=a2a \times a = a^2.
  3. Multiply outer terms: Next, we multiply the outer terms: a×(b)=aba \times (-b) = -ab.
  4. Multiply inner terms: Then, we multiply the inner terms: b×a=abb \times a = ab.
  5. Multiply last terms: Finally, we multiply the last terms of each binomial: b×(b)=b2b \times (-b) = -b^2.
  6. Combine all products: Now, we combine all the products: a2ab+abb2a^2 - ab + ab - b^2.
  7. Cancel out additive inverses: We notice that ab-ab and +ab+ab are additive inverses, so they cancel each other out: a2+0b2a^2 + 0 - b^2.
  8. Simplify the expression: Simplifying the expression, we are left with a2b2a^2 - b^2, which is the left-hand side of the original equation.

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