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Uche pumps gasoline at a rate of

18(L)/(min)". "
What is Uche's pumping rate in
(mL)/(s) ?

(mL)/(s)

Uche pumps gasoline at a rate of $18 \frac{\mathrm{L}}{\min }$ . $\newline$ What is Uche's pumping rate in $\frac{\mathrm{mL}}{\mathrm{s}}$ ? $\newline$ $\square$ $\frac{\mathrm{mL}}{\mathrm{s}}$

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Convert rates and measurements: customary units

Full solution

Q. Uche pumps gasoline at a rate of

18 \frac{\mathrm{L}}{\min }

.

\newline

What is Uche's pumping rate in

\frac{\mathrm{mL}}{\mathrm{s}}

?

\newline

\square

\frac{\mathrm{mL}}{\mathrm{s}}

Conversion Factors: To convert the pumping rate from liters per minute to milliliters per second, we need to know the conversion factors between liters and milliliters and between minutes and seconds. There are $1,000$ milliliters in a liter and $60$ seconds in a minute.
Given Pumping Rate: Uche's pumping rate is given as $18$ liters per minute. To convert this to milliliters, we multiply by $1,000$ (since there are $1,000$ milliliters in a liter). $\newline$ Calculation: $18 \, \text{L/min} \times 1,000 \, \text{mL/L} = 18,000 \, \text{mL/min}$
Convert to Milliliters: Now, to convert the rate from milliliters per minute to milliliters per second, we divide by $60$ (since there are $60$ seconds in a minute). $\newline$ Calculation: $18,000$ mL/min $\div$ $60$ s/min = $300$ mL/s

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