Two parabolas graphed in the xy plane have the equations y=2(x−3)2−7 and y=−(x+a)2+2, where a is a constant. For what value of a will the two parabolas have the same axis of symmetry?Choose 1 answer:(A) 3(B) −3(C) 6(D) −6
Q. Two parabolas graphed in the xy plane have the equations y=2(x−3)2−7 and y=−(x+a)2+2, where a is a constant. For what value of a will the two parabolas have the same axis of symmetry?Choose 1 answer:(A) 3(B) −3(C) 6(D) −6
Finding the axis of symmetry for the first parabola: The axis of symmetry for a parabola in the form y=A(x−h)2+k is the vertical line x=h. Let's find the axis of symmetry for the first parabola.The first parabola is given by y=2(x−3)2−7.The axis of symmetry for this parabola is x=3.
Finding the axis of symmetry for the second parabola: Now let's find the axis of symmetry for the second parabola.The second parabola is given by y=−(x+a)2+2.The axis of symmetry for this parabola is x=−a.
Setting the values of equal: For the two parabolas to have the same axis of symmetry, the values of from both equations must be equal.So we set equal to -a.\newline333 = -a
Solving for aaa: Solving for aaa, we get:\newlinea=−3a = -3a=−3