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The inclination (tilt) of an amusement park ride is accelerating at a rate of
2160(" degrees ")/(min^(2)).
What is the ride's acceleration rate in
(" degrees ")/(s^(2)) ?

(" degrees ")/(s^(2))

The inclination (tilt) of an amusement park ride is accelerating at a rate of $2160 \frac{\text { degrees }}{\min ^{2}}$ . $\newline$ What is the ride's acceleration rate in $\frac{\text { degrees }}{\mathrm{s}^{2}}$ ? $\newline$ $\frac{\text { degrees }}{\mathrm{s}^{2}}$

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Convert rates and measurements: customary units

Full solution

Q. The inclination (tilt) of an amusement park ride is accelerating at a rate of

2160 \frac{\text { degrees }}{\min ^{2}}

.

\newline

What is the ride's acceleration rate in

\frac{\text { degrees }}{\mathrm{s}^{2}}

?

\newline

\frac{\text { degrees }}{\mathrm{s}^{2}}

Convert to seconds: To convert the acceleration rate from degrees per minute squared to degrees per second squared, we need to know how many seconds are in one minute. $\newline$ There are $60$ seconds in one minute. Therefore, to convert from per minute squared to per second squared, we need to divide the given rate by $60$ squared (since there are $60$ seconds in a minute and we are dealing with a squared quantity). $\newline$ Calculation: $\frac{2160 \text{ degrees/min}^2}{60^2}$
Perform calculation: Now, we perform the calculation. $\newline$ $\frac{2160}{60^2} = \frac{2160}{3600}$
Simplify fraction: Simplify the fraction by dividing $2160$ by $3600$ . $\newline$ $\frac{2160}{3600} = 0.6$ $\newline$ So, the ride's acceleration rate is $0$ . $6$ degrees per second squared.

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