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T=277+4s
The temperature in kelvin, 
T, of a resistor in a circuit 
s seconds after connecting a battery is given by the equation. For how many seconds does the battery need to be connected for the temperature to increase by 1 kelvin?
Choose 1 answer:
(A) 0.25
(B) 4
(c) 69
(D) 277

T=277+4s T=277+4 s \newlineThe temperature in kelvin, T T , of a resistor in a circuit s s seconds after connecting a battery is given by the equation. For how many seconds does the battery need to be connected for the temperature to increase by 11 kelvin?\newlineChoose 11 answer:\newline(A) 00.2525\newline(B) 44\newline(C) 6969\newline(D) 277277

Full solution

Q. T=277+4s T=277+4 s \newlineThe temperature in kelvin, T T , of a resistor in a circuit s s seconds after connecting a battery is given by the equation. For how many seconds does the battery need to be connected for the temperature to increase by 11 kelvin?\newlineChoose 11 answer:\newline(A) 00.2525\newline(B) 44\newline(C) 6969\newline(D) 277277
  1. Given Equation: We are given the equation T=277+4sT = 277 + 4s, where TT is the temperature in kelvin and ss is the time in seconds after connecting a battery. We want to find out how long it takes for the temperature to increase by 11 kelvin. Let's denote the initial temperature as TinitialT_{\text{initial}} and the final temperature as TfinalT_{\text{final}}. Since the increase is by 11 kelvin, we have Tfinal=Tinitial+1T_{\text{final}} = T_{\text{initial}} + 1.
  2. Initial Temperature: Let's set up the equation for the initial temperature. We have Tinitial=277+4sinitialT_{\text{initial}} = 277 + 4s_{\text{initial}}, where sinitials_{\text{initial}} is the initial time. Since we are looking for the time after the battery is connected, we can assume sinitials_{\text{initial}} to be 00. Therefore, Tinitial=277+4(0)=277T_{\text{initial}} = 277 + 4(0) = 277.
  3. Final Temperature: Now let's set up the equation for the final temperature. We have Tfinal=277+4sfinalT_{\text{final}} = 277 + 4s_{\text{final}}, where sfinals_{\text{final}} is the time after which the temperature has increased by 11 kelvin. Since Tfinal=Tinitial+1T_{\text{final}} = T_{\text{initial}} + 1, we can write 277+4sfinal=277+1277 + 4s_{\text{final}} = 277 + 1.
  4. Solving for Time: Solving the equation 277+4sfinal=278277 + 4s_{\text{final}} = 278, we subtract 277277 from both sides to isolate the term with sfinals_{\text{final}}. This gives us 4sfinal=2782774s_{\text{final}} = 278 - 277, which simplifies to 4sfinal=14s_{\text{final}} = 1.
  5. Finding Time: To find sfinals_{\text{final}}, we divide both sides of the equation by 44. This gives us sfinal=14s_{\text{final}} = \frac{1}{4}, which is equal to 0.250.25 seconds.

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