Solve the system of equations. {:[-9x+4y=6],[9x+5y=-33],[x=◻],[y=◻]:}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'x' as the coefficients are the same in both equations but with opposite signs.Identify operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients are opposite.Add equations to eliminate x: Add the equations to eliminate 'x'. (-9x + 4y) + (9x + 5y) = 6 + (-33) -9x + 4y + 9x + 5y = -27 4y + 5y = -27 9y = -27Solve for y: Solve for 'y'. Dividing both sides of the equation by 9 gives us y = -27 / 9. y = -3Substitute y into first equation: Substitute y = -3 into the first equation to solve for 'x'. Substitute y = -3 in -9x + 4y = 6. We get -9x + 4(-3) = 6. Simplify to get -9x - 12 = 6. Add 12 to both sides, we get -9x = 18.Solve for x: Solve for 'x'. Dividing both sides of the equation by -9 gives us x = 18 / -9. x = -2Write the solution as a coordinate point: Write the solution as a coordinate point. The solution is (-2, -3).

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Solve the system of equations.

{:[-9x+4y=6],[9x+5y=-33],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -9 x+4 y=6 \\ 9 x+5 y=-33 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -9 x+4 y=6 \\ 9 x+5 y=-33 \\ x=\square \\ y=\square \end{array}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate ' $x$ ' as the coefficients are the same in both equations but with opposite signs.
Identify operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients are opposite.
Add equations to eliminate x: Add the equations to eliminate 'x'. $(-9x + 4y) + (9x + 5y) = 6 + (-33)$ $\newline$ $-9x + 4y + 9x + 5y = -27$ $\newline$ $4y + 5y = -27$ $\newline$ $9y = -27$
Solve for y: Solve for 'y'. Dividing both sides of the equation by $9$ gives us $y = -\frac{27}{9}$ . $\newline$ $y = -3$
Substitute y into first equation: Substitute $y = -3$ into the first equation to solve for 'x'. Substitute $y = -3$ in $-9x + 4y = 6$ . We get $-9x + 4(-3) = 6$ . Simplify to get $-9x - 12 = 6$ . Add $12$ to both sides, we get $-9x = 18$ .
Solve for x: Solve for 'x'. Dividing both sides of the equation by $-9$ gives us $x = \frac{18}{-9}$ . $\newline$ $x = -2$
Write the solution as a coordinate point: Write the solution as a coordinate point. The solution is $(-2, -3)$ .