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Solve the system of equations.

{:[-7y-4x=1],[7y-2x=53],[x=◻],[y=◻]:}

Solve the system of equations.\newline7y4x=17y2x=53x=y= \begin{array}{l} -7 y-4 x=1 \\ 7 y-2 x=53 \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline7y4x=17y2x=53x=y= \begin{array}{l} -7 y-4 x=1 \\ 7 y-2 x=53 \\ x=\square \\ y=\square \end{array}
  1. Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate ' extit{y}' by adding the two equations since the coefficients of ' extit{y}' are opposite.
  2. Add equations to eliminate variable: Add the equations to eliminate 'y'. (7y4x)+(7y2x)=1+53(-7y - 4x) + (7y - 2x) = 1 + 537y+7y4x2x=54-7y + 7y - 4x - 2x = 540y6x=540y - 6x = 54This simplifies to 6x=54-6x = 54.
  3. Solve for x: Solve for 'x'. Dividing both sides of the equation by 6-6 gives us x=9x = -9.
  4. Substitute xx into equation to solve for yy: Substitute x=9x = -9 into one of the original equations to solve for 'yy'. We can use the second equation 7y2x=537y - 2x = 53. Substituting x=9x = -9, we get 7y2(9)=537y - 2(-9) = 53. This simplifies to 7y+18=537y + 18 = 53.
  5. Solve for y: Solve for 'y'. Subtract 1818 from both sides to get 7y=357y = 35. Dividing both sides by 77 gives us y=5y = 5.
  6. Write solution as coordinate point: Write the solution as a coordinate point. The solution is (9,5)(-9, 5).

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