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Solve the system of equations.

{:[5y-4x=-7],[2y+4x=14],[x=◻],[y=◻]:}

Solve the system of equations.\newline5y4x=72y+4x=14x=y= \begin{array}{l} 5 y-4 x=-7 \\ 2 y+4 x=14 \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline5y4x=72y+4x=14x=y= \begin{array}{l} 5 y-4 x=-7 \\ 2 y+4 x=14 \\ x=\square \\ y=\square \end{array}
  1. Identify operation to eliminate variable: Identify the operation to eliminate one of the variables. In this case, we can add the two equations directly to eliminate 'xx'.
  2. Add equations to eliminate 'x': Add the equations (5y4x)+(2y+4x)=7+14(5y - 4x) + (2y + 4x) = -7 + 14 to eliminate 'x'.\newline5y4x+2y+4x=7+145y - 4x + 2y + 4x = -7 + 14\newline7y=77y = 7
  3. Solve for 'y': Solve for 'y'. Dividing both sides of the equation by 77 gives us y=1y = 1.\newline7y7=77 \frac{7y}{7} = \frac{7}{7} \newliney=1y = 1
  4. Substitute y=1y = 1 to solve for 'x': Substitute y=1y = 1 into one of the original equations to solve for 'x'. We can use the second equation 2y+4x=142y + 4x = 14.\newline2(1)+4x=142(1) + 4x = 14\newline2+4x=142 + 4x = 14
  5. Solve for 'x': Solve for 'x'. Subtract 22 from both sides to isolate 4x4x.\newline4x=1424x = 14 - 2\newline4x=124x = 12
  6. Write the solution as a coordinate point: Divide both sides by 44 to find the value of 'x'.\newline4x4=124\frac{4x}{4} = \frac{12}{4}\newlinex=3x = 3
  7. Write the solution as a coordinate point: Divide both sides by 44 to find the value of 'x'.\newline4x4=124\frac{4x}{4} = \frac{12}{4}\newlinex=3x = 3Write the solution as a coordinate point. The solution is (3,1)(3, 1).

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