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Solve the system of equations.

{:[2y-3x=-27],[5y+3x=6],[x=◻],[y=◻]:}

Solve the system of equations.\newline2y3x=275y+3x=6x=y= \begin{array}{l} 2 y-3 x=-27 \\ 5 y+3 x=6 \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline2y3x=275y+3x=6x=y= \begin{array}{l} 2 y-3 x=-27 \\ 5 y+3 x=6 \\ x=\square \\ y=\square \end{array}
  1. Identify operation to eliminate variable: Identify the operation to eliminate one of the variables. In this case, we can add the two equations directly to eliminate 'xx'.
  2. Add equations to eliminate 'x': Add the equations (2y3x)+(5y+3x)=27+6(2y - 3x) + (5y + 3x) = -27 + 6.\newlineThis simplifies to 2y+5y=27+62y + 5y = -27 + 6, which gives us 7y=217y = -21.
  3. Solve for 'y': Solve for 'y'. Dividing both sides of the equation by 77 gives us y=217y = -\frac{21}{7}, which simplifies to y=3y = -3.
  4. Substitute yy into equation: Substitute y=3y = -3 into one of the original equations to solve for 'xx'. We can use the first equation 2y3x=272y - 3x = -27. Substituting yy gives us 2(3)3x=272(-3) - 3x = -27.
  5. Simplify equation and solve for 'x': Simplify the equation and solve for 'x'. This gives us 63x=27-6 - 3x = -27. Adding 66 to both sides gives us 3x=27+6-3x = -27 + 6, which simplifies to 3x=21-3x = -21.
  6. Divide both sides to solve for 'x': Divide both sides by 3-3 to solve for 'x'. This gives us x=213x = \frac{-21}{-3}, which simplifies to x=7x = 7.
  7. Write solution as coordinate point: Write the solution as a coordinate point. The solution is (7,3)(7, -3).

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