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Solve for
x.
Enter the solutions from least to greatest.

{:[(2x-1)(x+4)=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for $x$ . $\newline$ Enter the solutions from least to greatest. $\newline$ $(2 x-1)(x+4)=0$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Find the roots of factored polynomials

Full solution

Q. Solve for

x

.

\newline

Enter the solutions from least to greatest.

\newline

(2 x-1)(x+4)=0

\newline

lesser

x=

\newline

greater

x=

Factorization: Factored polynomial: $2x-1)(x+4)=0\ To find the roots of this polynomial, we need to set each factor equal to zero and solve for \$x$ .
First Factor Solution: First factor: $2x - 1 = 0$ $\newline$ To find the value of $x$ , we add $1$ to both sides of the equation. $\newline$ $2x - 1 + 1 = 0 + 1$ $\newline$ $2x = 1$ $\newline$ Now, we divide both sides by $2$ to solve for $x$ . $\newline$ $\frac{2x}{2} = \frac{1}{2}$ $\newline$ $x = \frac{1}{2}$
Second Factor Solution: Second factor: $x + 4 = 0$ $\newline$ To find the value of $x$ , we subtract $4$ from both sides of the equation. $\newline$ $x + 4 - 4 = 0 - 4$ $\newline$ $x = -4$
Final Solutions: We have found two solutions for $x$ : $x = \frac{1}{2}$ $x = -4$ Now we need to list the solutions from least to greatest. $-4 < \frac{1}{2}$

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