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Solve for
x.

3x-91 > -87quad OR
quad21 x-17 > 25
Choose 1 answer:
(A)
x > 2
(B)
x > (4)/(3)
(C)
(4)/(3) < x < 2
D There are no solutions
(E) All values of
x are solutions

Solve for $x$ . $\newline$ $3 x-91>-87 \quad$ OR $\quad 21 x-17>25$ $\newline$ Choose $1$ answer: $\newline$ (A) $x>2$ $\newline$ (B) $x>\frac{4}{3}$ $\newline$ (C) $\frac{4}{3}<x<2$ $\newline$ D There are no solutions $\newline$ (E) All values of $x$ are solutions

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Solve a quadratic equation by factoring

Full solution

Q. Solve for

x

.

\newline

3 x-91>-87 \quad

OR

\quad 21 x-17>25

\newline

Choose

1

answer:

\newline

(A)

x>2

\newline

(B)

x>\frac{4}{3}

\newline

(C)

\frac{4}{3}<x<2

\newline

D There are no solutions

\newline

(E) All values of

x

are solutions

Solve inequality $3x - 91 > -87$ : First, let's solve the inequality $3x - 91 > -87$ . Add $91$ to both sides to isolate the term with $x$ . $3x - 91 + 91 > -87 + 91$ $3x > 4$ Now, divide both sides by $3$ to solve for $x$ . $\frac{3x}{3} > \frac{4}{3}$ $x > \frac{4}{3}$
Isolate the term with $x$ : Next, let's solve the inequality $21x - 17 > 25$ . Add $17$ to both sides to isolate the term with $x$ . $21x - 17 + 17 > 25 + 17$ $21x > 42$ Now, divide both sides by $21$ to solve for $x$ . $\frac{21x}{21} > \frac{42}{21}$ $x > 2$
Divide both sides by $3$ to solve for $x$ : Now we have two inequalities to consider: $x > \frac{4}{3}$ and $x > 2$ . Since $x$ must be greater than both $\frac{4}{3}$ and $2$ , we take the larger value, which is $2$ . Therefore, the solution is $x > 2$ .

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