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Solve for
x.

-18 x+21 > -15quad" OR "quad20 x-13 >= 27
Choose 1 answer:
(A)
x < -2 or
x >= 2
(B)
x=-2
(C)
x >= 2
D There are no solutions
(E) All values of
x are solutions

Solve for $x$ . $\newline$ $-18 x+21>-15 \quad \text { OR } \quad 20 x-13 \geq 27$ $\newline$ Choose $1$ answer: $\newline$ (A) $x<-2$ or $x \geq 2$ $\newline$ (B) $x=-2$ $\newline$ (C) $x \geq 2$ $\newline$ D There are no solutions $\newline$ (E) All values of $x$ are solutions

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Solve rational equations

Full solution

Q. Solve for

x

.

\newline

-18 x+21>-15 \quad \text { OR } \quad 20 x-13 \geq 27

\newline

Choose

1

answer:

\newline

(A)

x<-2

or

x \geq 2

\newline

(B)

x=-2

\newline

(C)

x \geq 2

\newline

D There are no solutions

\newline

(E) All values of

x

are solutions

Solve first inequality: Solve the first inequality $-18x + 21 > -15$ . $\newline$ Subtract $21$ from both sides to isolate the term with $x$ . $\newline$ $-18x + 21 - 21 > -15 - 21$ $\newline$ $-18x > -36$ $\newline$ Now, divide both sides by $-18$ , remembering to reverse the inequality sign because we are dividing by a negative number. $\newline$ $x < \frac{-36}{-18}$ $\newline$ $x < 2$
Solve second inequality: Solve the second inequality $20x - 13 \geq 27$ . $\newline$ Add $13$ to both sides to isolate the term with $x$ . $\newline$ $20x - 13 + 13 \geq 27 + 13$ $\newline$ $20x \geq 40$ $\newline$ Now, divide both sides by $20$ . $\newline$ $x \geq \frac{40}{20}$ $\newline$ $x \geq 2$
Combine solutions: Combine the solutions from Step $1$ and Step $2$ . $\newline$ The first inequality gives us $x < 2$ . $\newline$ The second inequality gives us $x \geq 2$ . $\newline$ The only number that satisfies both conditions is $x = 2$ .

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