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Select the equivalent expression.

((3^(6))/(y^(-5)))^(2)=?
Choose 1 answer:
(A) 
(3^(6))/(y^(-10))
(B) 
3^(12)*y^(10)
(C) 
(3^(12))/(y^(-5))

Select the equivalent expression.\newline(36y5)2=?\left(\frac{3^{6}}{y^{-5}}\right)^{2}=\,?\newlineChoose 11 answer:\newline(A) 36y10\frac{3^{6}}{y^{-10}}\newline(B) 312y103^{12}y^{10}\newline(C) 312y5\frac{3^{12}}{y^{-5}}

Full solution

Q. Select the equivalent expression.\newline(36y5)2=?\left(\frac{3^{6}}{y^{-5}}\right)^{2}=\,?\newlineChoose 11 answer:\newline(A) 36y10\frac{3^{6}}{y^{-10}}\newline(B) 312y103^{12}y^{10}\newline(C) 312y5\frac{3^{12}}{y^{-5}}
  1. Apply power of power rule: Apply the power of a power rule.\newlineThe power of a power rule states that (am)n=amn(a^{m})^{n} = a^{m*n}. We will apply this rule to both the numerator and the denominator separately.\newline(36y5)2=362y52\left(\frac{3^{6}}{y^{-5}}\right)^{2} = \frac{3^{6*2}}{y^{-5*2}}
  2. Calculate exponents: Calculate the exponents.\newlineNow we will calculate the exponents for both 33 and yy.\newline3(62)=3123^{(6*2)} = 3^{12}\newliney(52)=y10y^{(-5*2)} = y^{-10}
  3. Rewrite expression with calculated exponents: Rewrite the expression with the calculated exponents.\newlineThe expression now becomes:\newline(312)/(y10)(3^{12})/(y^{-10})
  4. Simplify expression: Simplify the expression.\newlineSince y10y^{-10} is in the denominator, we can move it to the numerator to make the exponent positive.\newline(312)/(y10)=312y10(3^{12})/(y^{-10}) = 3^{12} \cdot y^{10}
  5. Choose correct answer: Choose the correct answer.\newlineThe simplified expression is 312×y103^{12} \times y^{10}, which corresponds to answer choice (B)(B).

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