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Multiply and simplify the following complex numbers:

(-2-3i)*(-5-2i)

Multiply and simplify the following complex numbers:\newline(23i)(52i) (-2-3 i) \cdot(-5-2 i)

Full solution

Q. Multiply and simplify the following complex numbers:\newline(23i)(52i) (-2-3 i) \cdot(-5-2 i)
  1. Distribute terms: Distribute each term of the first complex number by each term of the second complex number.\newline(23i)×(52i)=(2×5)+(2×2i)+(3i×5)+(3i×2i)(-2-3i) \times (-5-2i) = (-2 \times -5) + (-2 \times -2i) + (-3i \times -5) + (-3i \times -2i)
  2. Calculate products: Calculate the products of the real numbers and the products involving the imaginary unit ii.
    ($2×5(\$-2 \times -5) = 1010\)
    ($2×2i(\$-2 \times -2i) = 4i4i\)
    ($3i×5(\$-3i \times -5) = 15i15i\)
    ($3i×2i(\$-3i \times -2i) = 6i26i^2\)
    Since i2=1i^2 = -1, we replace 6i26i^2 with ($2×5(\$-2 \times -511.
  3. Combine like terms: Combine like terms, which includes adding the real numbers and the imaginary numbers separately.\newline1010 (real) +(6)+ (-6) (real) +4i+ 4i (imaginary) +15i+ 15i (imaginary)\newline106+4i+15i=4+19i10 - 6 + 4i + 15i = 4 + 19i
  4. Write final answer: Write the final answer in the standard form of a complex number, which is a+bia + bi.\newlineThe final answer is 4+19i4 + 19i.

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