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Isabella paid one of her bills late and owed a 
4% late fee. Her total, with the late fee, was 
$780. How much was Isabella's original bill in dollars?

Isabella paid one of her bills late and owed a 4% 4 \% late fee. Her total, with the late fee, was $780 \$ 780 . How much was Isabella's original bill in dollars?

Full solution

Q. Isabella paid one of her bills late and owed a 4% 4 \% late fee. Her total, with the late fee, was $780 \$ 780 . How much was Isabella's original bill in dollars?
  1. Setting up the equation: We know:\newlineTotal amount paid with late fee: $780\$780\newlineLate fee percentage: 4%4\%\newlineTo find the original bill amount, we need to understand that the total amount paid is 104%104\% of the original bill (100%100\% of the bill + 4%4\% late fee).\newlineLet's represent the original bill amount as xx.\newlineSo, 104%104\% of xx is equal to $780\$780.\newlineWe can write this as 1.04x=$7801.04x = \$780.\newlineNow, we need to solve for xx to find the original bill amount.
  2. Solving for the value xx: To solve for xx, we divide both sides of the equation by 1.041.04. \newlinex=$(780)1.04x = \frac{\$(780)}{1.04} \newlineNow, we perform the division to find the original bill amount. \newlinex=$(750)x = \$(750)

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