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If 
(1)/(5)h+25=d, which of the following expressions is equivalent to 
h ?
Choose 1 answer:
(A) 
(1)/(5)d-5
(B) 
(1)/(5)d+25
(c) 
5d-125
(D) 
5d-25

If 15h+25=d \frac{1}{5} h+25=d , which of the following expressions is equivalent to h h ?\newlineChoose 11 answer:\newline(A) 15d5 \frac{1}{5} d-5 \newline(B) 15d+25 \frac{1}{5} d+25 \newline(C) 5d125 5 d-125 \newline(D) 5d25 5 d-25

Full solution

Q. If 15h+25=d \frac{1}{5} h+25=d , which of the following expressions is equivalent to h h ?\newlineChoose 11 answer:\newline(A) 15d5 \frac{1}{5} d-5 \newline(B) 15d+25 \frac{1}{5} d+25 \newline(C) 5d125 5 d-125 \newline(D) 5d25 5 d-25
  1. Isolate hh in equation: We have the equation:\newline15h+25=d\frac{1}{5}h + 25 = d\newlineTo solve for hh, we need to isolate hh on one side of the equation.
  2. Subtract 2525: Subtract 2525 from both sides of the equation to move the constant term to the other side:\newline15h+2525=d25\frac{1}{5}h + 25 - 25 = d - 25
  3. Simplify equation: Simplify both sides of the equation: \newline15h=d25\frac{1}{5}h = d - 25
  4. Multiply by 55: Multiply both sides of the equation by 55 to solve for hh:5×(15)h=5×(d25)5 \times \left(\frac{1}{5}\right)h = 5 \times (d - 25)
  5. Final solution: Simplify the multiplication: \newlineh=5d125h = 5d - 125

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