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How many solutions does the following equation have? -25 z+1+35 z=10 z+1 Choose 1 answer: (A) No solutions (B) Exactly one solution (c) Infinitely many solutions

How many solutions does the following equation have?\newline−25z+1+35z=10z+1-25 z + 1 + 35 z = 10 z + 1\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

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Q. How many solutions does the following equation have?\newline−25z+1+35z=10z+1-25 z + 1 + 35 z = 10 z + 1\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Combine like terms: Combine like terms on the left side of the equation. \newline−25z+1+35z-25z + 1 + 35z \newline=10z+1= 10z + 1
  2. Simplify left side: Simplify the left side by adding the coefficients of zz.(−25+35)z+1(-25 + 35)z + 1 =10z+1= 10z + 1
  3. Calculate coefficient of z: Calculate the simplified coefficient of z on the left side. \newline10z+110z + 1 \newline= 10z+110z + 1
  4. Observe identical sides: Observe that both sides of the equation are identical.\newlineSince 10z+110z + 1 is equal to 10z+110z + 1 for all values of zz, the equation has infinitely many solutions.

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