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Find the missing factor G that makes the equality true. {:[18y^(3)=(G)(2y^(2))],[G=◻]:}

Find the missing factor G G that makes the equality true.\newline18y3=(G)(2y2)G=□ \begin{array}{l} 18 y^{3}=(G)\left(2 y^{2}\right) \\ G=\square \end{array}

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Integer inequalities with absolute valuesright chevron icon

Full solution

Q. Find the missing factor G G that makes the equality true.\newline18y3=(G)(2y2)G=□ \begin{array}{l} 18 y^{3}=(G)\left(2 y^{2}\right) \\ G=\square \end{array}
  1. Understand the equation: Understand the equation given. We have 18y3=G⋅2y218y^3 = G \cdot 2y^2, and we need to find the value of GG that makes this equation true.
  2. Divide both sides: Divide both sides of the equation by 2y22y^2 to solve for GG. This gives us G=18y32y2G = \frac{18y^3}{2y^2}.
  3. Simplify the right side: Simplify the right side of the equation. Divide 1818 by 22 to get 99, and subtract the exponents of yy (since they have the same base and we are dividing) to get y(3−2)y^{(3-2)} which is y1y^1 or simply yy. So, G=9yG = 9y.

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