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$Find the missing factor B that makes the equality true. {:[21y^(4)=(B)(7y^(3))],[B=◻]:}$

Find the missing factor $B$ that makes the equality true. $\newline$ $\begin{array}{l} 21 y^{4}=(B)\left(7 y^{3}\right) \\ B=\square \end{array}$

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Integer inequalities with absolute values

Full solution

Q. Find the missing factor

B

that makes the equality true.

\newline

\begin{array}{l} 21 y^{4}=(B)\left(7 y^{3}\right) \\ B=\square \end{array}

Identify equation and goal: Identify the given equation and the goal. We are given the equation $21y^4 = B \cdot 7y^3$ and we need to find the value of $B$ that makes this equation true.
Divide by $7y^3$ : Divide both sides of the equation by $7y^3$ to solve for $B$ . This gives us $B = \frac{21y^4}{7y^3}$ .
Simplify right side: Simplify the right side of the equation. Divide $21$ by $7$ and $y^4$ by $y^3$ . This gives us $B = 3y^{(4-3)} = 3y$ .
Check result: Check the result to ensure there are no mathematical errors. $3y \times 7y^3 = 21y^4$ , which is the original equation, so the solution is correct.

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