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Complete the equation of the line through 
(3,-1) and 
(4,7).
Use exact numbers.

y=

Complete the equation of the line through (3,1) (3,-1) and (4,7) (4,7) .\newlineUse exact numbers.\newliney= y=

Full solution

Q. Complete the equation of the line through (3,1) (3,-1) and (4,7) (4,7) .\newlineUse exact numbers.\newliney= y=
  1. Finding the Slope: To find the equation of a line, we need to determine the slope (mm) and the y-intercept (bb) of the line. The slope can be found using the formula m=(y2y1)(x2x1)m = \frac{(y_2 - y_1)}{(x_2 - x_1)}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points the line passes through.
  2. Calculating the Slope: Let's calculate the slope using the points (3,1)(3, -1) and (4,7)(4, 7).\newlinem=7(1)43m = \frac{7 - (-1)}{4 - 3}\newlinem=7+11m = \frac{7 + 1}{1}\newlinem=81m = \frac{8}{1}\newlinem=8m = 8
  3. Using Point-Slope Form: Now that we have the slope, we can use point-slope form to write the equation of the line. The point-slope form is yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line.
  4. Plugging in Values: Using the point (3,1)(3, -1) and the slope m=8m = 8, we can plug these into the point-slope form.y(1)=8(x3)y - (-1) = 8(x - 3)y+1=8x24y + 1 = 8x - 24
  5. Converting to Slope-Intercept Form: To get the equation in slope-intercept form y=mx+by = mx + b, we need to isolate yy.y=8x241y = 8x - 24 - 1y=8x25y = 8x - 25

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