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Bulan rows on a crew team. Her team rows their boat at a split (rate) of
2
m
i
n
500
m
\frac{2 \mathrm{~min}}{500 \mathrm{~m}}
500
m
2
min
.
\newline
What is Bulan's team's rowing rate in
m
min
\frac{\mathrm{m}}{\min }
m
i
n
m
?
\newline
□
\square
□
m
min
\frac{\mathrm{m}}{\min }
m
i
n
m
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Math Problems
Algebra 1
Convert rates and measurements: customary units
Full solution
Q.
Bulan rows on a crew team. Her team rows their boat at a split (rate) of
2
m
i
n
500
m
\frac{2 \mathrm{~min}}{500 \mathrm{~m}}
500
m
2
min
.
\newline
What is Bulan's team's rowing rate in
m
min
\frac{\mathrm{m}}{\min }
m
i
n
m
?
\newline
□
\square
□
m
min
\frac{\mathrm{m}}{\min }
m
i
n
m
Reciprocal of given rate:
To convert the rate from
(
2
min
)
/
(
500
m
)
(2 \, \text{min})/(500 \, \text{m})
(
2
min
)
/
(
500
m
)
to
(
m
)
/
(
min
)
(\text{m})/(\text{min})
(
m
)
/
(
min
)
, we need to take the reciprocal of the given rate.
New rate calculation:
So, the new rate is
(
500
m
)
/
(
2
min
)
(500 \, \text{m})/(2 \, \text{min})
(
500
m
)
/
(
2
min
)
.
Simplification of rate:
Now, we simplify the rate by dividing
500
500
500
by
2
2
2
.
Final simplified rate:
The simplified rate is
250
m/min
.
250\,\text{m/min}.
250
m/min
.
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