Bernardo invested $2,000 in two different types of stocks. The first type cost $32 per share, and the second cost $48 per share. Between the two types, he purchased a total of 47 shares. How many shares of the $48-per-share stock did he purchase?
Q. Bernardo invested $2,000 in two different types of stocks. The first type cost $32 per share, and the second cost $48 per share. Between the two types, he purchased a total of 47 shares. How many shares of the $48-per-share stock did he purchase?
Denote shares and equation: Let's denote the number of shares of the $32 stock as x and the number of shares of the $48 stock as y. We know that Bernardo purchased a total of 47 shares, so we can write the first equation as:x+y=47
Total investment equation: We also know that the total amount invested is $2,000. Since the first type of stock costs $32 per share and the second type costs $48 per share, we can write the second equation based on the total investment as: 32x+48y=2000
Solving system of equations: Now we have a system of two equations with two variables:1) x+y=472) 32x+48y=2000We can solve this system using substitution or elimination. Let's use the substitution method. From the first equation, we can express x in terms of y:x=47−y
Substitute x into equation: Substitute x=47−y into the second equation: 32(47−y)+48y=2000 Now, distribute the 32 into the parentheses: 32×47−32y+48y=2000
Simplify and combine terms: Simplify and combine like terms: 1504−32y+48y=200016y=2000−150416y=496
Solve for y: Divide both sides by 16 to solve for y:y = 16496y = 31 We have the value for y, which represents the number of shares of the $48 stock. Bernardo purchases 31 shares of the $48-per-share-stock.
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