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Bernardo invested 
$2,000 in two different types of stocks. The first type cost 
$32 per share, and the second cost 
$48 per share. Between the two types, he purchased a total of 47 shares. How many shares of the 
$48-per-share stock did he purchase?

Bernardo invested $2,000 \$ 2,000 in two different types of stocks. The first type cost $32 \$ 32 per share, and the second cost $48 \$ 48 per share. Between the two types, he purchased a total of 4747 shares. How many shares of the $48 \$ 48 -per-share stock did he purchase?

Full solution

Q. Bernardo invested $2,000 \$ 2,000 in two different types of stocks. The first type cost $32 \$ 32 per share, and the second cost $48 \$ 48 per share. Between the two types, he purchased a total of 4747 shares. How many shares of the $48 \$ 48 -per-share stock did he purchase?
  1. Denote shares and equation: Let's denote the number of shares of the $32\$32 stock as xx and the number of shares of the $48\$48 stock as yy. We know that Bernardo purchased a total of 4747 shares, so we can write the first equation as:\newlinex+y=47x + y = 47
  2. Total investment equation: We also know that the total amount invested is $2,000\$2,000. Since the first type of stock costs $32\$32 per share and the second type costs $48\$48 per share, we can write the second equation based on the total investment as: \newline32x+48y=200032x + 48y = 2000
  3. Solving system of equations: Now we have a system of two equations with two variables:\newline11) x+y=47x + y = 47\newline22) 32x+48y=200032x + 48y = 2000\newlineWe can solve this system using substitution or elimination. Let's use the substitution method. From the first equation, we can express xx in terms of yy:\newlinex=47yx = 47 - y
  4. Substitute xx into equation: Substitute x=47yx = 47 - y into the second equation: 32(47y)+48y=200032(47 - y) + 48y = 2000 Now, distribute the 3232 into the parentheses: \newline32×4732y+48y=200032\times47 - 32y + 48y = 2000
  5. Simplify and combine terms: Simplify and combine like terms: \newline150432y+48y=20001504 - 32y + 48y = 2000\newline16y=2000150416y = 2000 - 1504\newline16y=49616y = 496
  6. Solve for y: Divide both sides by 1616 to solve for y:\newliney = 49616\frac{496}{16}\newliney = 3131 \newline We have the value for yy, which represents the number of shares of the $48\$48 stock. \newline Bernardo purchases 3131 shares of the $48\$48-per-share-stock.

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