At Charlie's Cinema, a total of 1,200 adult and child movie tickets were sold to bring in $10,875 in ticket sales one evening. If each child ticket costs $7.50 and each adult ticket costs $10.00, how many adult tickets were sold that evening?
Q. At Charlie's Cinema, a total of 1,200 adult and child movie tickets were sold to bring in $10,875 in ticket sales one evening. If each child ticket costs $7.50 and each adult ticket costs $10.00, how many adult tickets were sold that evening?
Equations given: Let's denote the number of child tickets sold as C and the number of adult tickets sold as A. We are given two equations based on the total number of tickets sold and the total revenue from ticket sales:1. C+A=1,200 (total tickets equation)2. 7.50C+10A=10,875 (total revenue equation)We need to solve this system of equations to find the value of A, which represents the number of adult tickets sold.
Rearranging total tickets equation: First, we can rearrange the total tickets equation to express C in terms of A: C=1,200−AThis will allow us to substitute the value of C in the total revenue equation.
Substituting C into total revenue equation: Now, let's substitute C=1,200−A into the total revenue equation:7.50(1,200−A)+10A=10,875Expanding this, we get:9,000−7.50A+10A=10,875Combining like terms, we have:2.50A=10,875−9,000So, the equation now is:2.50A=1,875
Solve for A: To find A, we divide both sides of the equation by 2.50:A=2.501,875A=750
Dividing both sides of the equation: We have found that the number of adult tickets sold, A, is 750. To ensure we haven't made any mistakes, we can check our work by substituting A back into the original total tickets equation:C+A=1,200C+750=1,200C=1,200−750C=450Since C represents the number of child tickets, we can also check the total revenue by calculating:7.50C+10A=7.50(450)+10(750)=3,375+7,500=7500The total revenue checks out, so our solution for A is correct.
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