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At Charlie's Cinema, a total of 1,200 adult and child movie tickets were sold to bring in 
$10,875 in ticket sales one evening. If each child ticket costs 
$7.50 and each adult ticket costs 
$10.00, how many adult tickets were sold that evening?

At Charlie's Cinema, a total of 11,200200 adult and child movie tickets were sold to bring in $10,875 \$ 10,875 in ticket sales one evening. If each child ticket costs $7.50 \$ 7.50 and each adult ticket costs $10.00 \$ 10.00 , how many adult tickets were sold that evening?

Full solution

Q. At Charlie's Cinema, a total of 11,200200 adult and child movie tickets were sold to bring in $10,875 \$ 10,875 in ticket sales one evening. If each child ticket costs $7.50 \$ 7.50 and each adult ticket costs $10.00 \$ 10.00 , how many adult tickets were sold that evening?
  1. Equations given: Let's denote the number of child tickets sold as CC and the number of adult tickets sold as AA. We are given two equations based on the total number of tickets sold and the total revenue from ticket sales:\newline11. C+A=1,200C + A = 1,200 (total tickets equation)\newline22. 7.50C+10A=10,8757.50C + 10A = 10,875 (total revenue equation)\newlineWe need to solve this system of equations to find the value of AA, which represents the number of adult tickets sold.
  2. Rearranging total tickets equation: First, we can rearrange the total tickets equation to express CC in terms of AA: \newlineC=1,200AC = 1,200 - A\newlineThis will allow us to substitute the value of CC in the total revenue equation.
  3. Substituting C into total revenue equation: Now, let's substitute C=1,200AC = 1,200 - A into the total revenue equation:\newline7.50(1,200A)+10A=10,8757.50(1,200 - A) + 10A = 10,875\newlineExpanding this, we get:\newline9,0007.50A+10A=10,8759,000 - 7.50A + 10A = 10,875\newlineCombining like terms, we have:\newline2.50A=10,8759,0002.50A = 10,875 - 9,000\newlineSo, the equation now is:\newline2.50A=1,8752.50A = 1,875
  4. Solve for AA: To find AA, we divide both sides of the equation by 2.502.50:A=1,8752.50A = \frac{1,875}{2.50}\newlineA=750A = 750
  5. Dividing both sides of the equation: We have found that the number of adult tickets sold, AA, is 750750. To ensure we haven't made any mistakes, we can check our work by substituting AA back into the original total tickets equation:\newlineC+A=1,200C + A = 1,200\newlineC+750=1,200C + 750 = 1,200\newlineC=1,200750C = 1,200 - 750\newlineC=450C = 450\newlineSince CC represents the number of child tickets, we can also check the total revenue by calculating:\newline7.50C+10A=7.50(450)+10(750)7.50C + 10A = 7.50(450) + 10(750)\newline=3,375+7,500= 3,375 + 7,500\newline=7500= 7500\newlineThe total revenue checks out, so our solution for AA is correct.

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