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Apply the distributive property to factor out the greatest common factor of all three terms.

24 c+36 d+18=

Apply the distributive property to factor out the greatest common factor of all three terms.\newline24c+36d+18= 24 c+36 d+18=

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Q. Apply the distributive property to factor out the greatest common factor of all three terms.\newline24c+36d+18= 24 c+36 d+18=
  1. Identify GCF of coefficients: Identify the greatest common factor (GCF) of the numerical coefficients 2424, 3636, and 1818.\newlineTo find the GCF, we list the factors of each number and find the largest factor that is common to all three.\newlineFactors of 2424: 11, 22, 33, 44, 66, 88, 363600, 2424\newlineFactors of 3636: 11, 22, 33, 44, 66, 363688, 363600, 1818, 3636\newlineFactors of 1818: 11, 22, 33, 66, 363688, 1818\newlineThe GCF is 66.
  2. Use distributive property: Use the distributive property to factor out the GCF from each term.\newlineThe distributive property states that a(b+c)=ab+aca(b + c) = ab + ac.\newlineApplying this to our expression, we get:\newline6(24c6+36d6+186)6\left(\frac{24c}{6} + \frac{36d}{6} + \frac{18}{6}\right)\newlinePerform the division for each term:\newline6(4c+6d+3)6(4c + 6d + 3)
  3. Perform division for each term: Check the factored expression to ensure that when the GCF is distributed back to each term, we get the original expression.\newline6×4c=24c6 \times 4c = 24c\newline6×6d=36d6 \times 6d = 36d\newline6×3=186 \times 3 = 18\newlineThe original expression is recovered, so there is no math error.

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