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An object is launched from a platform. Its height (in meters), x seconds after the launch, is modeled by: h(x)=-5(x-4)^(2)+180 What is the height of the object at the time of launch? meters

An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by:\newlineh(x)=−5(x−4)2+180h(x)=-5(x-4)^{2}+180\newlineWhat is the height of the object at the time of launch? meters\text{meters}

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Q. An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by:\newlineh(x)=−5(x−4)2+180h(x)=-5(x-4)^{2}+180\newlineWhat is the height of the object at the time of launch? meters\text{meters}
  1. Identify Launch Time: Identify the time of launch.\newlineThe time of launch is when x=0x = 0 seconds, since xx represents the time after the launch.
  2. Substitute x=0x=0: Substitute x=0x = 0 into the height equation.\newlineh(x)=−5(x−4)2+180h(x) = -5(x-4)^2 + 180\newlineh(0)=−5(0−4)2+180h(0) = -5(0-4)^2 + 180
  3. Calculate Launch Height: Calculate the height at the time of launch.\newlineh(0)=−5(−4)2+180h(0) = -5(-4)^2 + 180\newlineh(0)=−5(16)+180h(0) = -5(16) + 180\newlineh(0)=−80+180h(0) = -80 + 180\newlineh(0)=100h(0) = 100

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