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A circle in the 
xy-plane has its center on the line 
y=1. If the point 
(2,-3) lies on the circle and the radius is 4 , which of the following could be the center of the circle?
Choose 1 answer:
(A) 
(2,1)
(B) 
(2,-3)
(c) 
(4,1)
(D) 
(-4,1)

A circle in the xy x y -plane has its center on the line y=1 y=1 . If the point (2,3) (2,-3) lies on the circle and the radius is 44 , which of the following could be the center of the circle?\newlineChoose 11 answer:\newline(A) (2,1) (2,1) \newline(B) (2,3) (2,-3) \newline(C) (4,1) (4,1) \newline(D) (4,1) (-4,1)

Full solution

Q. A circle in the xy x y -plane has its center on the line y=1 y=1 . If the point (2,3) (2,-3) lies on the circle and the radius is 44 , which of the following could be the center of the circle?\newlineChoose 11 answer:\newline(A) (2,1) (2,1) \newline(B) (2,3) (2,-3) \newline(C) (4,1) (4,1) \newline(D) (4,1) (-4,1)
  1. Problem and Given Information: Understand the problem and the given information.\newlineWe are given that the center of the circle lies on the line y=1y=1, which means that the yy-coordinate of the center is 11. We also know that the circle passes through the point (2,3)(2,-3) and has a radius of 44 units.
  2. Distance Formula for x-coordinate: Use the distance formula to find the possible x-coordinates of the center.\newlineThe distance formula is d=((x2x1)2+(y2y1)2)d = \sqrt{((x_2 - x_1)^2 + (y_2 - y_1)^2)}, where dd is the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2). Here, we know the distance (radius) is 44, one point is (2,3)(2,-3), and the other point (the center) has a y-coordinate of 11. We need to find the x-coordinate of the center.
  3. Solving for x-coordinate: Plug in the known values into the distance formula and solve for the x-coordinate.\newlineLet the x-coordinate of the center be xx. Then we have:\newline4=((x2)2+(1(3))2)4 = \sqrt{((x - 2)^2 + (1 - (-3))^2)}\newline16=(x2)2+(1+3)216 = (x - 2)^2 + (1 + 3)^2\newline16=(x2)2+1616 = (x - 2)^2 + 16\newline0=(x2)20 = (x - 2)^2\newlinex2=0x - 2 = 0\newline$x = \(2\)
  4. Checking Possible Centers: Check the possible centers against the given options.\(\newline\)We have found that the x-coordinate of the center is \(2\), and we know the y-coordinate is \(1\) (since the center lies on the line \(y=1\)). Therefore, the center of the circle is \((2,1)\).
  5. Matching Center with Answer Choices: Match the found center with the given answer choices.\(\newline\)The center \((2,1)\) matches with answer choice \((A)\).

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