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A certain factory produces and sells 
C computers per month. It costs 
x dollars to produce a single computer, and the factory sells each computer for 
y dollars. Their monthly net profit is 10,000 dollars.
Write an equation that relates 
C, 
x, and 
y.

A certain factory produces and sells C C computers per month. It costs x x dollars to produce a single computer, and the factory sells each computer for y y dollars. Their monthly net profit is 1010,000000 dollars.\newlineWrite an equation that relates C C , x x , and y y .

Full solution

Q. A certain factory produces and sells C C computers per month. It costs x x dollars to produce a single computer, and the factory sells each computer for y y dollars. Their monthly net profit is 1010,000000 dollars.\newlineWrite an equation that relates C C , x x , and y y .
  1. Net Profit Calculation: The net profit for the factory is the total revenue from selling the computers minus the total cost of producing them, with the net profit given as $10,000\$10,000. We can express the total revenue as the number of computers sold, CC, times the selling price per computer, yy. So, the total revenue is CyCy.
  2. Total Revenue Calculation: Similarly, the total cost of producing the computers is the number of computers produced, CC, times the production cost per computer, xx. So, the total cost is CxCx.
  3. Total Cost Calculation: The net profit is the total revenue minus the total cost. We can write this as an equation: Net Profit=Total RevenueTotal Cost\text{Net Profit} = \text{Total Revenue} - \text{Total Cost}. Substituting the expressions for total revenue and total cost, we get: Net Profit=CyCx\text{Net Profit} = C_y - C_x.
  4. Substituting Net Profit Value: Since the net profit is given as $10,000\$10,000, we can substitute this value into the equation. This gives us: 10,000=CyCx10,000 = C_y - C_x.
  5. Factoring Out C in the Equation: To make the equation relate CC, xx, and yy, we can rewrite it by factoring out CC from the right side of the equation. This gives us: 10,000=C(yx)10,000 = C(y - x).

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