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9 Given that 
x-y=5 and 
xy=-6(1)/(2), find the value of 
x^(2)+y^(2).

99 Given that xy=5 x-y=5 and xy=612 x y=-6 \frac{1}{2} , find the value of x2+y2 x^{2}+y^{2} .

Full solution

Q. 99 Given that xy=5 x-y=5 and xy=612 x y=-6 \frac{1}{2} , find the value of x2+y2 x^{2}+y^{2} .
  1. Expand and Square: We know that (xy)2=x22xy+y2(x - y)^2 = x^2 - 2xy + y^2.\newlineLet's square the first equation: (xy)2=52(x - y)^2 = 5^2.
  2. Calculate Value: Now calculate the square of 55: 52=255^2 = 25.
  3. Substitute and Simplify: Substitute the value of xyxy from the second equation into the expanded form of (xy)2(x - y)^2. So, x22xy+y2=x22×(6×12)+y2x^2 - 2xy + y^2 = x^2 - 2\times(-6\times\frac{1}{2}) + y^2.
  4. Correct Calculation: Calculate the double of xyxy: 2×(6×12)=132\times(-6\times\frac{1}{2}) = -13. Oops, made a mistake here. It should be 2×(6×12)=62\times(-6\times\frac{1}{2}) = -6.

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