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9-(4)/(3)x=-7

$9-\frac{4}{3} x=-7$

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Evaluate integers raised to rational exponents

Full solution

Q.

9-\frac{4}{3} x=-7

Isolate x term: First, let's isolate the term with $x$ by moving the $9$ to the other side of the equation. $9 - \left(\frac{4}{3}\right)x = -7$ $\left(- \frac{4}{3}\right)x = -7 - 9$
Combine right side: Now, let's combine the numbers on the right side. $\newline$ - $(-\frac{4}{3})x = -16$
Divide by $-(4/3)$ : Next, we need to get $x$ by itself, so we'll divide both sides by $-(4/3)$ . $\newline$ $x = -16 / -(4/3)$
Multiply by reciprocal: To divide by a fraction, we multiply by its reciprocal. $x = -16 \times \left(-\frac{3}{4}\right)$
Multiply the numbers: Now, let's multiply the numbers. $x = \frac{48}{4}$
Divide to find $x$ : Finally, we divide $48$ by $4$ to find $x$ . $\newline$ $x = 12$

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