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Let’s check out your problem:
Evaluate the expression.
\newline
8
⋅
9
+
3
(
6
−
7
)
8 \cdot 9 + 3(6 - 7)
8
⋅
9
+
3
(
6
−
7
)
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Math Problems
Algebra 1
Multiply radical expressions
Full solution
Q.
Evaluate the expression.
\newline
8
⋅
9
+
3
(
6
−
7
)
8 \cdot 9 + 3(6 - 7)
8
⋅
9
+
3
(
6
−
7
)
Perform Multiplication:
First, we need to perform the multiplication part of the expression.
\newline
Calculate
8
8
8
times
9
9
9
.
\newline
8
×
9
=
72
8 \times 9 = 72
8
×
9
=
72
Solve Parentheses:
Next, we need to solve the expression inside the parentheses.
\newline
Calculate
6
6
6
minus
7
7
7
.
\newline
6
−
7
=
−
1
6 - 7 = -1
6
−
7
=
−
1
Multiply Result:
Now, we multiply the result from Step
2
2
2
by
3
3
3
. Calculate
3
3
3
times
−
1
-1
−
1
.
3
×
−
1
=
−
3
3 \times -1 = -3
3
×
−
1
=
−
3
Add Results:
Finally, we add the result from Step
1
1
1
to the result from Step
3
3
3
.
\newline
Add
72
72
72
and
−
3
-3
−
3
.
\newline
72
+
(
−
3
)
=
69
72 + (-3) = 69
72
+
(
−
3
)
=
69
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