2. 8865 Specimen Paper Q7A game is played with a fair 6-sided die. A player throws this die, and if the result is 2,3,4 or 5 that result is the player's score. If the result of the player's throw is 1 or 6 , the player throws second time and the score is the sum of the two numbers from the two throws. Events A and are defined as follows:5:123456789A: the player's score is 5,6,7,8 or 9 ,B: the player has two throws.(i) Draw a tree diagram to represent this situation, showing all possible outcomes.[2](ii) Show that P(A)=31.(iii) Find the probability that a player gets a score of 5, 6, 7, 8 or 9 in two throws.(iv) Describe what is meant by the probability P(A∣B) in this context and find its value. [3
Q. 2. 8865 Specimen Paper Q7A game is played with a fair 6-sided die. A player throws this die, and if the result is 2,3,4 or 5 that result is the player's score. If the result of the player's throw is 1 or 6 , the player throws second time and the score is the sum of the two numbers from the two throws. Events A and are defined as follows:5:123456789A: the player's score is 5,6,7,8 or 9 ,B: the player has two throws.(i) Draw a tree diagram to represent this situation, showing all possible outcomes.[2](ii) Show that P(A)=31.(iii) Find the probability that a player gets a score of 5, 6, 7, 8 or 9 in two throws.(iv) Describe what is meant by the probability P(A∣B) in this context and find its value. [3
Tree Diagram Branches: (i) For the tree diagram, we have two initial branches: rolling a 1 or 6, and rolling a 2, 3, 4, or 5. If a 1 or 6 is rolled, there's a second throw with six possible outcomes each. If a 2, 3, 4, or 5 is rolled, the game ends with that score.
Calculation of P(A): (ii) To calculate P(A), we consider the scores 5,6,7,8, or 9. Rolling a 2,3,4, or 5 on the first throw gives a score within A. The probability of rolling any of these four numbers on a fair die is 64 or 32. There are no other ways to get a score within A on the first throw, so P(A)=32, not 5,6,7,8,0 as stated in the question.