8 [N2010/II/7 modified] For events A and B, it is given that P(A)=0.7,P(B)=0.6 and P(A∣B′)=0.8. Find(i) P(A∩B′),(ii) P(A∪B),(iii) P(B′∣A).For a third event C, it is given that P(C)=0.5 and that A and C are independent.(iv) Find B1(v) Hence state an inequality satisfied by B2 in the form B3, where B4 and B5 are constants to be determined.
Q. 8 [N2010/II/7 modified] For events A and B, it is given that P(A)=0.7,P(B)=0.6 and P(A∣B′)=0.8. Find(i) P(A∩B′),(ii) P(A∪B),(iii) P(B′∣A).For a third event C, it is given that P(C)=0.5 and that A and C are independent.(iv) Find B1(v) Hence state an inequality satisfied by B2 in the form B3, where B4 and B5 are constants to be determined.
Divide Total Amount: First, we need to divide the total amount of tape needed by the amount of tape on each roll.So, we do 8,000cm÷2,000cm per roll.
Calculate Number of Rolls: Calculating that gives us 8,000÷2,000=4 rolls.