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885-5: MathXL for School: Practice & Problem Solving (LMS graded) Apr 2525 - 1111:5959 pm 88.55.PS18-18 Question Help The diagram shows a track composed of a rectangle with a semicircle on each end. The area of the rectangle is 2,8002,800 square meters. What is the perimeter of the track? Use 3.143.14 for pi. The perimeter of the track is \newlineoxed{ ext{ }}\newlineoxed{ ext{ }} (Round to the nearest tenth as needed.) Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check Answer Review Progress Question 88 of 88 Back Next

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Q. 885-5: MathXL for School: Practice & Problem Solving (LMS graded) Apr 2525 - 1111:5959 pm 88.55.PS18-18 Question Help The diagram shows a track composed of a rectangle with a semicircle on each end. The area of the rectangle is 2,8002,800 square meters. What is the perimeter of the track? Use 3.143.14 for pi. The perimeter of the track is \newlineoxed{ ext{ }}\newlineoxed{ ext{ }} (Round to the nearest tenth as needed.) Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check Answer Review Progress Question 88 of 88 Back Next
  1. Identify dimensions: Step 11: Identify the dimensions of the rectangle.\newlineSince the area of the rectangle is given as 2,8002,800 square meters, we need to find its length and width. However, without additional information about the ratio of length to width or one of these dimensions, we cannot determine the exact dimensions of the rectangle. We assume the length (LL) and width (WW) are such that L×W=2,800L \times W = 2,800.
  2. Calculate perimeter: Step 22: Calculate the perimeter of the rectangle.\newlineThe perimeter PP of a rectangle is calculated by the formula P=2(L+W)P = 2(L + W). Without the specific values of LL and WW, we cannot calculate this directly.

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